NORMINV
Returns the inverse of the normal cumulative distribution for the specified mean and standard deviation.
Syntax
expression.NORMINV(arg1, arg2, arg3);
expression
- A variable that represents a ApiWorksheetFunction class.
Parameters
Name | Required/Optional | Data type | Default | Description |
---|---|---|---|---|
arg1 | Required | ApiRange | ApiName | number | A probability corresponding to the normal distribution, a number between 0 and 1 inclusive. | |
arg2 | Required | ApiRange | ApiName | number | The arithmetic mean of the distribution. | |
arg3 | Required | ApiRange | ApiName | number | The standard deviation of the distribution, a positive number. |
Returns
number
Example
- Code
- Result
const worksheet = Api.GetActiveSheet();
let valueArr = [0.34, 7, 3];
// Place the numbers in cells
for (let i = 0; i < valueArr.length; i++) {
worksheet.GetRange("A" + (i + 1)).SetValue(valueArr[i]);
}
//method params
let probability = worksheet.GetRange("A1").GetValue();
let mean = worksheet.GetRange("A2").GetValue();
let standardDeviation = worksheet.GetRange("A3").GetValue();
let func = Api.GetWorksheetFunction();
let inv = func.NORMINV(probability, mean, standardDeviation);
worksheet.GetRange("C1").SetValue(inv);